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Refractive index
Refractive index (n) is the constant of proportionality in Snell’s law; hence
- Sin i/ sin r = n
- Therefore sin i/sin r=n=1/sin r/sin i
Examples
- Calculate the refractive index for light travelling from glass to air given that ang= 1.5
Solution
gna= 1/ang = 1/1.5=0.67
- Calculate the angle of refraction for a ray of light from air striking an air-glass interface, making an angle of 600 with the interface. (ang= 1.5)
Solution
Angle of incidence (i) = 900-600=300
1.5=sin 30o/sin r, sin r =sin 300/ 1.5=0.5/1.5
Sin r=0.3333, sin-10.3333= 19.50
R= 19.50
Refractive index in terms of velocity.
Refractive index can be given in terms of velocity by the use of the following equation;
1n2 = velocity of light in medium 1/velocity of light in medium 2
When a ray of light is travelling from vacuum to a medium the refractive index is referred to as absolute refractive index of the medium denoted by ‘n’
Refractive index of a material ‘n’=velocity of light in a vacuum/velocity of light in material ‘n’
The absolute refractive indices of some common materials is given below
Examples 1. A ray of light is incident on a water-glass interface as shown. Calculate ‘r’. (Take the refractive index of glass and water as 3/2 and 4/3 respectively)
- The refractive index of water is 4/3 and that of glass is 3/2. Calculate the refractive index of glass with respect to water.
Solution
- wng= gna×ang, but wna = 1/ anw=3/4
- wng=3/4×3/2=9/8= 1.13
Real and apparent depth
Consider the following diagram
The depth of the water OM is the real depth, and the distance IM is known as the apparent depth. OI is the distance through which the coin has been displaced and is known as the vertical displacement.
The relationship between refractive index and the apparent depth is given by;
Refractive index of a material=real depth/apparent depth
NB
This is true only if the object is viewed normally.
Example
A glass block of thickness 12 cm is placed on a mark drawn on a plain paper.
The mark is viewed normally through the glass. Calculate the apparent depth of the mark and hence the vertical displacement. (Refractive index of glass =3/2)
Solution
- ang= real depth/apparent depth
- apparent depth= real depth/ ang=(12×2)/3= 8 cm
- vertical displacement= 12-8=4 cm
Applications of refractive index
Total internal reflection
This occurs when light travels from a denser optical medium to a less dense medium. The refracted ray moves away from the normal until a critical angle is reached usually 900 where the refracted ray is parallel to the boundary between the two media.
If this critical angle is exceeded total internal reflection occurs and at this point no refraction occurs but the ray is reflected internally within the denser medium.
Relationship between the critical angle and refractive index.
Consider the following diagram
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From Snell’s law
- gnw = sin C/sin 900,but ang = 1/gna since sin 900 = 1
- Therefore ang= 1/sin C, hence sin C=1/n or n=1/sin C
Example
Calculate the critical angle of diamond given that its refractive index is 2.42
Solution
Sin C= 1/n=1/ 2.42= 0.4132= 24.40
Effects of total internal reflection
- Mirage: These are ‘pools of water’ seen on a tarmac road during a hot day.
They are also observed in very cold regions but the light curves in opposite direction such that a polar bear seems to be upside down in the sky.
- Atmospheric refraction: the earths’ atmosphere refracts light rays so that the sun can be seen even when it has set. Similarly the sun is seen before it actually rises.
Applications of total internal reflection
- Periscope: a prism periscope consists of two right angled glass prisms of angles 450,900 and 450 arranged as shown below. They are used to observe distant objects.
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- Prism binoculars: the arrangement of lenses and prisms is as shown below. Binoculars reduce the distance of objects such that they seem to be nearer.
- Pentaprism: used in cameras to change the inverted images formed into erect and actual image in front of the photographer.
- Optical fibre: this is a flexible glass rod of small diameter. A light entering through them undergoes repeated internal reflections.
They are used in medicine to observe or view internal organs of the body
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- Dispersion of white light:
the splitting of light into its constituent colours is known as dispersion. Each colour represents a different wavelength as they strike the prism and therefore refracted differently as shown.
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