Course Content
Properties of Matter
OBJECTIVES By the end of this topic , the trainee should be able to: 1.Explain the three states of matter. 2.Explain phenomenon of surface tension. 3.Explain gas laws.
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Measurement
OBJECTIVES By the end of this topic , the trainee should be able to: 1.State the basic and derived quantities of measurements 2.Describe quantities of measurements 3.State the SI units of quantities of measurements and their sub-multipliers 4.Convert units from one to another
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Pressure
OBJECTIVES By the end of this topic , the trainee should be able to: 1.Define pressure 2.Determine pressure in solids and fluids 3.Explain the type of instruments used in measurement of pressure of gases 4.Explain transmission of presure in liquids
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Force
OBJECTIVES By the end of this topic, the trainee should be able to: 1.Define force and its SI units 2.Explain types of force 3.Measure force 4.Work out calculations involving force 5.Explain Hooke’s law
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Hooke’s Law
Hooke's Law  is a law named after 17th century British physicist Robert Hooke, who sought to demonstrate the relationship between the forces applied to a spring and its elasticity.
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Moments
OBJECTIVES By the end of this topic, the trainee should be able to: 1. Define moments of a force 2.Explain principles of moments 3.Explain statics , dynamics and kinematics
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Velocity and Speed
OBJECTIVES By the end of this topic , the trainee should be able to : 1.Define speed and velocity 2.Explain types of motion 3.Determine Linear Determine Circular Motion
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Work and Power
OBJECTIVES By the end of this topic , the trainee should be able to: 1.Define work and power 2.Work out calculations involving work and power
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Energy
OBJECTIVES By the end of this topic, the trainee should be able to: 1.Define energy 2.Explain forms of energy 3.Explain law of conservation of energy
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Motion
OBJECTIVES By the end of this topic, the trainee should be able to: 1.Define motion 2.Explain causes of motion 3.Explain types of motion 4.Describe linear and circular motion
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Newton’s Laws of Motion
OBJECTIVES By the end of this topic, the trainee should be able to: 1.State Newton’s laws of motion 2.Explain relationships between mass and inertia 3.Explain significance of Newton’s laws of motion
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Heat and Heat Transfer
OBJECTIVES By the end of this topic, the trainee should be able to 1.Define temperature and heat 2.Describe instruments used to measure temperature 3.Explain modes of heat transfer 4.Explain factors that influence heat transfer 5.Explain heat capacity, specific heat capacity and specific latent heat of substances 6. Work out calorimetric calculations
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Light
OBJECTIVES By the end of this topic , the trainee should be able to: 1.Define light and its properties 2.Explain types of mirrors and lenses 3.Explain reflection and refraction of light 4. Explain the lens formulae
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WAVES
OBJECTIVES By the end of this topic , the trainee should be able to : 1. Define waves 2.Explain types of waves 3.Explain characteristics and properties of waves 4.Explain rectilinear propagation of waves 5.Describe refraction of waves 6.Describe sound and sound waves
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Electrostatics
OBJECTIVES By the end of this topic , the trainee should be able to: 1.Define electrostatics 2. Describe the working of electroscopes 3.Describe different methods of charging a body 4.Explain electric fields 5.Describe charge distribution on conductors’ surface 6. Describe capacitors and capacitance
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Magnetism and Electromagnetism
OBJECTIVES By the end of this topic, the trainee should be able to: 1.Define magnetism 2.Identify magnetic and non- magnetic materials 3.Explain properties of magnets 4.Describe magnetic field patterns 5.Describe making magnets 6.Explain domain theory of magnets 7.Describe magnetic effect of an electric current. 8. Describe electromagnets and electromagnetism 9.Describe electromagnetic induction
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Current Electricity
CURRENT ELECTRICITY OBJECTIVES By the end of this topic, the trainer should be able to: 1. Define current and electricity 2.Electric potential difference 3.Explain use of a meters, voltmeters and resistors 4.Explain ohm’s law 5. Explain Electromotive force and internal resistance 6.Describe production of electric current 7.Describe simple cells, Leclanche’ cell, dry cells and lea-acid accumulators 8.Describe mains electricity 9.Describe domestic wiring
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Electromagnetic Spectrum
OBJECTIVES By the end of this topic , the trainee should be able to: 1.Define magnetic spectrum 2. Explain properties of electromagnetic waves 3. Describe applications of electromagnetic radiation
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Radioactivity
OBJECTIVES By the end of this topic, the trainee should be able to: 1. Define radioactivity 2.Classify radiations 3.Explain the properties of radiation materials 4.Describe nuclear fission and nuclear fusion 5.Describe methods for detecting nuclear radiation 6.Describe activity and half-life of elements 7. Discuss hazards of radioactivity and their precautions 8. Outline the applications of radioactivity
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Cathode and X-Rays
OBJECTIVES By the end of this topic, the trainee should be able to: 1. Define cathode and X- rays 2.Explain production of cathode and X- ray 3.Explain properties of cathode and X- ray 4.Describe cathode ray oscilloscope (CRO) 5. Describe the applications of Cathode and X-rays
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Physics Techniques For Science Laboratory Technicians
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Newton’s Laws of Motion
As already discussed in the previous topic,motion of objects are caused by unbalanced forces that act on the objects. Therefore, forces are related to motions of objects.

This was discovered by Sir Isaac Newton ( 1642 – 1727 ). He stated three laws of motion .
Newton’s First Law Of Motion:
Newton’s first law of motion states that an object will continue in its state of rest or motion in a straight line unless it is acted upon by an external force.
Inertia:
Inertia is the unwillingness of an object in motion to stop moving or an object at rest to start moving.
Inertia simply means unwillingness. Every object is unwilling to do other wise apart from what its is doing at the moment. Inertia is inherent in every object and is a property of very matter. 
Mass:
Mass is the quantity of matter that is contained in an object. The more the quantity of matter that is contained in an object, the larger the mass of the object. Mass is measured in kilogram ( kg ). It is a scalar quantity.
Inertial Mass:
Inertial mass is a property of a matter which represent a resistance that the resistance f the object to any type of force.

Weight:
Weight of an object is the gravitational pull on the object. Or It can be defined as the force that is acting on the object due to the earth gravitational pull. Weight is measured in Newton. It is a vector quantity.

Relationship Between Inertia And Mass:
Mass of an object is the quantity of matter in the object. Mass of an object is a measure of the inertia of the object. The mass of an object determines the amount of inertia / resistance that the object will offer to a force that act on it and try to change its state. The more the mass of an object, the more the inertia of that object  will be, the more the resistance and the larger the force required to change the state of rest of the object or uniform motion .
Relationship Between Mass And Weight:
The relationship between mass and weight is the formula that connect mass and weight. This formula is used in calculations, to either calculate the weight of a given mass of object or to calculate the mass of a given weight.
The formula is :     weight = mass X acceleration due to gravity
                                 Weight = mX g
Worked Examples:
1. Calculate the weight of a mass 2.6gram.
      Data given in the question: 
      Mass = 225g = 225 /1000 = 0.225 kg.
       Formula:   weight =  mass  X  acceleration due to gravity
       Substitution:      weight = 0.225 X 10.  

weight = 2.25N
2. What is the mass of object whose weight is 35N? ( g = 10 m/s² )
        Data given in he question:
        Weight = 35 N, g = 10 m/s²
         Formula:  weight = mass * acceleration due to gravity
        Substitution:  35 = mass X 10
       Make mass the subject:    mass = 35 / 10.

mass = 3.5 kg 

Significance Of Newton’s First Law Of Motion:
The significance of Newton’s first law of motion is that, Newton’s first law  of motion make us to understand that inertia ( unwillingness ) is present in every object. 
Short Coming Of Newton’s First Law Of Motion:
Though Newton’s first law of motion make us to know that inertia is inherent in every object and also explain what force does on an object. Newton’s first law of motion does not suggest how force should be measured.

Newton’s Second Law Of Motion:
Newton’s second law of motion states that the rate of change of momentum is directly proportional to the force that caused the change and take place in the direction of the force.
The formula that connect force and mass is as stated below:
           Force = mass of object  X acceleration of the object 
          F = m X a
 Example 1:
1. Calculate the magnitude of the force that act on 12kg mass such that its acceleration is 1.75 m/s².
          Solution:
          Data given in the question:
        Mass = 12kg, acceleration = 1.75 m/s², force = ?
        Formula:  force = mass  X acceleration
      Substitution:    force = 12 X 1.75 
      Force = 21 Newtons
2. Given that 35 N force act on 2.6 kg mass. If the velocity of the object is 0.25 m/s, determine the acceleration of the  object.
          Solution:
Force = 35 N,  Mass=2.6 kg and velocity = 0.25 m/s
Formula:   Force = mass X acceleration
Substitution:  35 = 2.6 X  acceleration
Make acceleration the subject:    acceleration = 35 / 2.6
Acceleration = 13.46 m/s
3. An unbalance force of 25 N act on a 8.0 kg mass. What  acceleration does it gives to the mass?
Solution:
         Mass = 8.0 kg, force = 25 N, acceleration = ?
          Formula:  force = mass  X  acceleration
          Substitution:  25 = 8.0  X  acceleration 
          Make acceleration the subject:    acceleration = 25 / 8.0
          Acceleration = 3.13m/s²
Formula Of Newton’s Second Law Of Motion:
From the above statement of Newton’s second law of motion, the formula Newton’s second law of motion is obtained as follow:
              Mathematically,
          Force is directly proportional to rate of change in momentum
          Force ∞ rate of change in momentum
          Force ∞ change in momentum / time 
         Force ∞ (MV – MU) / time
       Factorize m:       Force ∞ m (  v – u ) / t
     Recall that acceleration

a = (final velocity v – initial velocity u) / time t
                       a = (v – u) / t
Substitute for a in the above equation: force = mass * acceleration
              Force ∞ mass = acceleration
Replay the proportional symbol with k:

  • force  = k X m X a.
    If constant k is 1, then the formula will become,
                        Force = ma

or

  • acceleration = force / mass
  • or
  • mass = force / acceleration

Examples:
1.  N object of mass 950g is pulled along a tarmac by a horizontal force of 20 N. A frictional force of 6 N opposed the motion . what is e acceleration of the stone?
             Solution:
             Data given in the question: 
           Mass of stone = 950 g = 950 / 1000 = 0.95 kg, force = 20 N , 
            frictional force = 6 N, 
Note: 
         Since friction force is present to oppose the motion of the object,     the force that moves the object or the effective force will be the difference between the give force and the frictional force.

Therefore,
          Effective force = force – friction force
         Effective force = 20 – 6 = 14 N 
       Formula:   force = mass X acceleration
       Substitution:      14 = 0.95  X  acceleration
        Make acceleration the subject:    acceleration = 14 / 0.95
                                 Acceleration = 14.74 m/s² 
2. A ball of mass 3 kg that is moving t a velocity of 26m/s is suddenly hit by a force of 6 N for 0.05 second. Find the new velocity of the object.
            Solution:
            Data given in the question:
         Mass = 3 kg, velocity =26 m/s, force = 6N, time = 0.05 second
Note:  Velocity of 26 m/s is given in the question and we  asked to calculate the new velocity of he object. That velocity is the initial velocity u, of the object while the new velocity that we are asked to calculate is the final velocity v, of the object.
              Formula:        

  Force = ( MV – MU ) / t
                               Force = m ( v – u ) / t
            Substitution:       6 = 3 ( v – 26 ) / 0.05
             Cross multiply:    6  X 0.05 = 3 ( v – 26 )
                                      0.3 = 3 ( v – 26 )
.                                     0.3 / 3 = v – 26
                                    0.10 = v – 26
             Make v the subject:    v = 0.10 + 26
                        V = 26.10 m/s

 

 

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